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2 years ago

I ADDED A PIC PLZZZZZZZZZ HELP I NEED AN ANSWER

Mathematics

2 answers:

disa [49]2 years ago

6 0

For every dollar you get 1/2 pound of grapes. It would cost 2$ per point of grapes

Sunny_sXe [5.5K]2 years ago

3 0

Answer:

For every dollar you spend, you can get 1/2 or .50 pounds of grape.

For each pound of grapes you would need 2 dollars.

Step-by-step explanation:

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Which one of these is the correct unit of measurement in finding volume?

kirill [66]

Answer:

feet cubic

Step-by-step explanation:

8 0

2 years ago

Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature e

Maslowich

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Equation of regression line :

Yˆ = −114.05+2.17X

X = Temperature in degrees Fahrenheit (°F)

Y = Number of bags of ice sold

On one of the observed days, the temperature was 82 °F and 66 bags of ice were sold.

X = 82°F ; Y = 66 bags of ice sold

1. Determine the number of bags of ice predicted to be sold by the LSR line, Yˆ, when the temperature is 82 °F.

X = 82°F

Yˆ = −114.05+2.17(82)

Y = - 114.05 + 177.94

Y = 63.89

Y = 64 bags

2. Compute the residual at this temperature.

Residual = Actual value - predicted value

Residual = 66 - 64 = 2 bags of ice

4 0

3 years ago

Find the value of x that makes lines u and v parallel.

Temka [501]

You set both expressions equal to each other, then solve for x. Your answer will be x=12

7 0

2 years ago

Read 2 more answers

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago

Solve the quadratic equation 3x^2 - 9x + 1 = 0 Give answer to 3 significant figures

Orlov [11]

Answer:

Either, (9+√69)/6 or (9-√69)/6

Step wise:

3x²-9x+1=0-------------------(i)

comparing equation onw with (ax²+bx+c=0), we get,

a=3, b=-9, c=1

now,

using Quadratic Formula,

(-b±√b²-4ac)/2a=x

{-(-9)±√(-9)²-4.3.1}/2.3=x

(9±√81-12)/6=x

(9±√69)/6=x

Taking +(ve) sign Taking -(ve) sign

(9+√69)/6=0 (9-√69)/6=0

∴(9+√69)/6=0 ∴(9-√69)/6=0

[∵They cannot be further solved]

6 0

3 years ago