Polynomials are not closed under division. When you divide polynomials it is possible to get quotients with negative exponents or with fractions that have exponents in the denominator, and neither of these could be included in polynomials.
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Step-by-step explanation:
radius of sphere, rs
radius of cylinder, rc
height of cylinder, h
given: h = rs = rc =r..eq1
volume of cylinder, vc = 27pi ft...eq2
volume of cylinder, vc = pi × rc^2 × h...eq3
volume of sphere, vs = 4/3(pi×rs^3)...eq4
subst for h & rs from eqn 1 in eqn 3...
vc = pi x r^2 x r= pi x r^3...eqn 5
subst for vc from eqn 2 in eqn 5...
=> 27 pi ft = pi x r^3
=> 27 = r^3
=> r = 3ft...eqn 6
subst for rs from eqn 1 in eqn 4
vs = 4/3 (pi x r^3)...eqn7
subst for pi x r^3 from eqn 5 in eqn 7
vs = 4/3 vc = 4/3 (27pi ft) = 36 pi ft
