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Gala2k [10]
2 years ago
10

Find the value of angel 0 to the nearest 10th​

Mathematics
1 answer:
BaLLatris [955]2 years ago
8 0

Answer: 36.9

Step-by-step explanation:

For this question you have to find out whether you are using Sin, Cos or Tan.

To work out which one you are using you can use SOH CAH TOA to help you.

SOH- The 'S' is for Sin, the 'O' and the 'H' is for Opposite over Hypotenuse.

CAH- The 'C' is for Cos and the 'A' and the 'H' is for Adjacent over Hypotenuse.

TOA- The 'T' is for Tan, the 'O' and the 'A is for Opposite over Adjacent.

As you have the Opposite (the side opposite the angle we're looking for) and the Adjacent (the side next to the angle were looking for) we would be using Tan.

So first you would have to write:

Tanθ=3/4

Then because we want Theta (θ) on it's own we would have to do the inverse to 'undo' the equation. Tan-1 is the inverse of Tan.

θ=Tan-1 3/4

To find the answer you would have to put it in your calculator.

θ=36.9

Hope this helps :)

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4/18 is closest to: 1/2 or 1 whole
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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Solve the system of equations using the substitution method.
Firdavs [7]

y = -1 + 3/8x

2x - 5y = 6

Substitute the first equation into the second equation, since y is already by itself.

2x - 5(-1 + 3/8x) = 6

2x + 5 - 15/8x = 6

2x - 15/8x = 1

16/8x - 15/8x = 1

1/8x = 1 Multiply 8 on both sides to get x by itself

x = 8


Plug x into either of the equations.

y = -1 + 3/8(8)

y = -1 + 3

y = 2


2(8) - 5y = 6

16 - 5y = 6

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(8,2)

8 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

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How much will Paul save per year
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