Y = -9x is proportional because its in the format y = kx
if you graph this equation youll see that it is a straight line that passes through the origin
i hope this helps!!
Answer:
1.38
Step-by-step explanation:
2 cups is one pint so if 3/4 is .38 then you would put it together to get 1.38
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

Answer:
n=-15
Step-by-step explanation:
5=n/5+8
subtract 8 on both sides
-3=n/5
multiply 5 on both sides
-15=n
Rectangle ABCD was rotated 90° counterclockwise around the origin and then translated 8 units down.