Help pls!! thanks in advanced!!

Ivy checks to see how many people are waiting in line. She notes that there are 120 possible line arrangements for the people th

Marina86 [1]

The total number of persons standing in the line waiting for ordering pizza are 5.

Explanation:

There are 5 people in total so the first place can be occupied by any of the 5 persons.

Secondly the second place in the line can be occupied by any of the 4 persons left.

Then the third place will be occupied by any remaining 3 persons as the front two places are already occupied.

Similarly the fourth place will be taken by any of the remaining two people. And lastly the last place will b filled by the last remaining person.

So the total number of ways will be 5*4*3*2*1 = 120 ways that is given in the question.

5 0

4 years ago

-5=3/4x-2 solve for x and please show your work!

Nookie1986 [14]

-5 = $\frac{3}{4} x$ - 2 equals x = -4.

First, simplify $\frac{3}{4} x$ to $\frac{3x}{4}$ . / Your problem should look like: -5 = $\frac{3x}{4}$ - 2.
Second, multiply both sides by 4. / Your problem should look like: -20 = 3x -8.
Third, add 8 to both sides. / Your problem should look like: -20 + 8 = 3x.
Fourth, simplify -20 + 8 to -12. / Your problem should look like: -12 = 3x.
Fifth, divide both sides by 3. / Your problem should look like: $- \frac{12}{3}$ = x.
Sixth, simplify $\frac{12}{3}$ to 4. / Your problem should look like: -4 = x.
Seventh, switch sides. / Your problem should look like: x = -4, which is your answer.

3 0

3 years ago

The heights of male are normally distributed with mean of 170 cm and standard deviation

Bumek [7]

Answer:

0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 170cm and standard deviation of 7.5 cm.

This means that $\mu = 170, \sigma = 7.5$