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3 years ago

Need help on range and domain

Mathematics

2 answers:

s2008m [1.1K]3 years ago

8 0

Answer:

domain is x and range is y

SashulF [63]3 years ago

6 0

Answer:

domain is your x value, and range is your y value.

Step-by-step explanation:

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Need help with this math problem

azamat

Answer: 12in

Step-by-step explanation:

Length+width+length+width

8 0

3 years ago

Read 2 more answers

plz i need help with this its due tmrw!! (also my other most recent question is #6 of this and it would be nice for answers for

kipiarov [429]

7. You have $367.50 after two years.

Start by converting 2.5% into a decimal (divide by 100) and multiplying by 350 to find the rate of interest per year.

350(0.025) = 8.75

Since it's for two years, multiply by two.

8.75 x 2 = 17.5.

Add it on to he original, and we have

350 + 17.5 = 367. 5, or $367.50 when converted back to money.

8. The annual interest rate is 2.4%

find the interest rate per year:

120/2.5 = 48 dollars per year. this is the interest amount, we want to find the interest rate. To do this, find what % of 2000 that 48 is equal to.

Set up a system of equations and cross multiply.

$\frac{48}{2000} = \frac{x}{100}$

2000x = 48(100) > 2000x = 4800

2000/2000x = 4800/2000 > x = 2.4

So, the interest rate is 2.4%.

9. the interest paid is $300 after six months, and $600 after a year.

Find the interest rate, similar to problem 7.

3000 x 0.2 = 600. This means the interest paid is $600 a year. In six months, the total will be half, or $300.

10. four years.

Find interest rate.

200(0.035) = $7/year

Remember that value. Subtract needed from current.

228 - 200 = $28.

So, we have an interest rate of $7 a year and we need $28. Normally, we'd solve using an expression, but in this case we can use simple multiplication. Knowing that 7 x 4 = 28, We can decide that it will take four years.

5 0

2 years ago

Simplify √ 96/8 a.√2/4 b.1/2√3 c.4√3/√2 d. 2√3

VARVARA [1.3K]

The first one is: √ 96/8=2 √ 3

5 0

2 years ago

What is the value of x,if x=3²

KatRina [158]

Answer:

x=9

Step-by-step explanation:

x = 3^2

x = 3*3

x=9

7 0

2 years ago

Read 2 more answers

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago