The first step for solving this is to move the variable to the left side and then change its sign.
10 - 11d + 5d > - 4
Now move the constant to the right side and change its sign.
-11d + 5d > -4 - 10
Collect the terms with a
d variable.
-6d > -4 - 10
Calculate the difference on the right side.
-6d > -14
Lastly,, divide both sides of the inequality by -6 and flip the inequality sign to find your final answer.
d <

Let me know if you have any further questions.
:)
A = c/sin C, and b by the proportion b/sin B = c/sin C.
a/sin 37° = 4380/sin 109°
a sin 109° = 4380 sin 37°
a = 4380 sin 37°/sin 109° ≈ 2787.8
b/sin 34° = 4380/sin 109°
b sin 109° = 4380 sin 34°
b = 4380 sin 34°/sin 109° ≈ 2590.4
Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.
<h3>What is the
area of the right-angle triangle?</h3>
The area of the right-angle triangle is given as
A = 1/2 x B x H
Where B is the base and H is the height of the right triangle.
We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.
α₁ = 40°
AO = OC = 7.8 cm
Then the area of the triangle will be
Area = 1/2 x 7.8 x 7.8 x tan40°
Area = 22.53 square cm
More about the area of the right-angle triangle link is given below.
brainly.com/question/16653962
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