Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Group 1:
μ1 = 59.7
s1 = 2.8
n1 = sample size = 12
Group 2:
μ2 = 64.7
s2 = 8.3
n2 = sample size = 15
α = 0.1
Assume normal distribution and equ sample variance
A.)
Null and alternative hypothesis
Null : μ1 = μ2
Alternative : μ1 < μ2
B.)
USing the t test
Test statistic :
t = (m1 - m2) / S(√1/n1 + 1/n2)
S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))
S = √(((12 - 1)2.8^2 + (15 - 1)8.3^2) / (12 + 15 - 2))
S = 6.4829005
t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)
t = - 5 / 2.5108165
tstat = −1.991384
Decision rule :
If tstat < - tα, (n1+n2-2) ; reject the Null
tstat < t0.1,25
From t table :
-t0.1, 25 = - 1.3163
tstat = - 1.9913
-1.9913 < - 1.3163 ; Hence reject the Null
Answer:
Y intersect and X intersect
0, the slope and y-intercept is 0
<h3>
Answer:</h3>
A net is shown with 3 rectangles attached side by side all with width 2 centimeters. The length of the first and third rectangle is 9 centimeters and the middle is 7 centimeters. Attached to the middle rectangle below are 3 rectangles with a length of 7 centimeters. The width of these rectangles are 9 centimeters, 2 centimeters, and 9 centimeters.
<h3>
Step-by-step explanation:</h3>
The area of a rectangular prism is the area of 6 surfaces. That is, 3 pairs of surfaces. Each of the three pairs will have one of the sets of dimensions ...
- length × width
- length × height
- width × height
In order for a net to be a net useful for calculating the prism surface area, it must have 3 pairs of rectangles with these dimensions. The description above matches that requirement.
___
Please note that no two surfaces with the same pair of dimensions are adjacent.
Did you attach a picture to this, It could be my internet but it’s not showing up on my screen
