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3 years ago

Find the variable (this is special right triangles unit)

Mathematics

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

a= 10sqrt(2) , b= 10

Step-by-step explanation:

In the picture above that you can see the explanation of solution.

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Solve the given number problem.

Evgesh-ka [11]

I would say -26 because -22, -24, -26=-72

6 0

3 years ago

Read 2 more answers

Suppose that you earned a bachelor's degree and now you're teaching high school. The school district offers teachers the oppor

harkovskaia [24]

Answer:

A ) The Amount which will be saved after five years is $ 5742.4

B ) The compound Interest is $ 1742.4

Step-by-step explanation:

The Principal deposited at the end of each year = $ 4000

The rate of interest = 7.5 % compounded annually

The time period = 5 years

From compounded method :

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

or, Amount = $ 4000 × $(1+\dfrac{\textrm 7.5}{100})^{\textrm 5}$

Or, Amount = $ 4000 × $(1.0075)^{5}$

or, Amount = $ 4000 × 1.4356

∴ Amount = $ 5742.4

A ) The Amount which will be saved after five years is $ 5742.4

B ) The compound Interest = Amount - principal

Or, C I = $ 5742.4 - $ 4000 is $ 1742.4 Answer

8 0

3 years ago

Solve for x <br> -2^2(-5x+10)=100

masha68 [24]

Answer:

$x=7$

Step-by-step explanation:

Hi there!

$-2^2(-5x+10)=100$

Solve -2^2:

$-4(-5x+10)=100$

Divide both sides by -4:

$\displaystyle \frac{ -4(-5x+10)}{-4}=\frac{100}{-4} \\\\-5x+10=-25$

Subtract 10 from both sides:

$-5x+10-10=-25-10\\-5x=-35$

Divide both sides by -5:

$\displaystyle \frac{-5x}{-5} = \frac{-35}{-5} \\\\x=7$

Therefore, x = 7.

I hope this helps!

3 0

3 years ago

All values of x <br> 5 ( x + 10 )^2 − 30 = − 5 <br> Plzzzz

Sedaia [141]

I got -7. 76 or rounded to -8. If right can you please mark me brainliest?

6 0

3 years ago

Hi! I was wondering if you could help with this question please :)

Makovka662 [10]

Answer:

$R=\frac{QJ}{I^2t}$

Step-by-step explanation:

So we have the equation:

$Q=\frac{I^2Rt}{J}$

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

$(J)Q=(J)\frac{I^2Rt}{J}$

Simplify the right:

$JQ=I^2Rt$

We can rewrite our equation as:

$JQ=R(I^2t)$

So, to isolate the R variable, divide both sides by I²t:

$\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}$

The right side cancels, so:

$R=\frac{QJ}{I^2t}$

And we are done!

7 0

3 years ago