Y=y, equals x+x+x, plus graph
1 answer:
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The equation is 
.
We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).
The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.
We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant
. You can see that from the quadratic formula. This holds true for both answers A and C, so to find the correct one, we remember that when the coefficient a of the 
term is positive, the graph opens upwards, so we choose C.
We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).
The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.
We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant
Answer:
Cos A = 24/25 & Tan A = 7/24
Step-by-step explanation:
See the attached figure.
Construct a right triangle and sign one angle as A
So, Sin A = opposite/hypotenuse = 7/25
∴hypotenuse = 25 and opposite = 7
∴ adjacent = √(25² - 7² ) = √576 = 24
∴ Cos A = adjacent/hypotenuse = 24/25
And
Tan A = opposite/adjacent = 7/24
