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2 years ago

Name the four basic steps to take when solving a word problem.

Mathematics

1 answer:

Grace [21]2 years ago

3 0

answer

Step-by-step explanation:

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Determine the amount of money you would have if you invested $15,000 dollars for 11 years at 3% annual interest compounded conti

tamaranim1 [39]

Answer:

The amount after 3 years of investment is $20763 .

Step-by-step explanation:

Given as :

The principal invested = p =$15,000

The rate of interest = r = 3% compounded annually

The time period = t = 11 years

Let The Amount after 3 years = $ A

From Compounded method

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, A = $15,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 11}$

Or, A = $15,000 × $(1.03)^{11}$

Or, A = $15,000 × 1.3842

Or, A = $20763

So, Amount = A = $20763

Hence The amount after 3 years of investment is $20763 . Answer

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3 years ago

Solve for x, given the equation square root of x + 9 -4 = 1

saveliy_v [14]

Answer:

x = -4

Step-by-step explanation:

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3 years ago

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I need help! please domain range and end behavior of f(x)=1-x^2

Reptile [31]

Answer:

Here's a screenshot. Hope this helps

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3 years ago

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SHOW YOUR WORK, PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

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3 years ago

Please help again I dont get this

e-lub [12.9K]

Answer:

help me with my problem

Step-by-step explanation:

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