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Doss [256]
2 years ago
14

Name the four basic steps to take when solving a word problem.

Mathematics
1 answer:
Grace [21]2 years ago
3 0

answer

Step-by-step explanation:

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A scale has a percent error of 7% the scale reads the mass of a book as 450 g.
Bess [88]
B, is the correct answer.
7% of 450 is 31.5
We add 31.5 to 450 to find out highest possible error, and subtract 31.5 from 450 to find out lowest possible error.
3 0
3 years ago
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What is the center of the circle with this equation is (x+2)²+(y-4)²=41?
OLga [1]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Solve the system using substitution.
Iteru [2.4K]
Q=2p+1
subsitute 2p+1 for q in other eqaution


4p+2q=8
4p+2(2p+1)=8
4p+4p+2=8
8p+2=8
minus 2 both sides
8p=6
divide both sides by 8
p=6/8
p=3/4
sub back
q=2p+1
q=2(3/4)+1
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q=3/2+2/2
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8 0
3 years ago
A recipe for muffins calls for 9 cups of sugar . Jose accidentally put in 10 cups . How many extra cups did he put in
Ann [662]
10 cups of sugar - 9 cups of sugar = 1 cup of sugar that he accidentally put in :)
8 0
3 years ago
The three trapezoids have the same base lengths, but different angle measures. Which trapezoid has the greatest area? Explain.
Luden [163]

Steps I took:

I drew out a circle with a radius of 1 and drew a trapezoid inscribed in the top portion of it. I outlined the rectangle within the trapezoid and the two right triangles within it. This allowed me to come to the conclusion, using the pythagorean theorem, that the height of the trapezoid is <span><span>h=<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span></span><span>h=<span>1−<span><span>x2</span>4</span></span></span></span>

The formula for the area of a trapezoid is <span><span>A=<span><span>a+b</span>2</span>(h)</span><span>A=<span><span>a+b</span>2</span>(h)</span></span> I am basically solving for the <span>aa</span> here and so far I have:

<span><span>A=<span><span>x+2</span>2</span>(<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span>1−<span><span>x2</span>4</span></span>)</span></span>

I simplified this in order to be able to easily take the derivative of it as such:

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span>4</span><span>−−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>4</span>)</span></span>

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>2</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>2</span>)</span></span>

<span><span>A=(<span>14</span>)(x+2)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)</span><span>A=(<span>14</span>)(x+2)(<span>4−<span>x2</span></span>)</span></span>

Then I took the derivative:

<span><span><span>A′</span>=<span>14</span>[(1)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span><span><span>A′</span>=<span>14</span>[(1)(<span>4−<span>x2</span></span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span></span>

This all simplified to:

<span><span><span>A′</span>=<span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]</span><span><span>A′</span>=<span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]</span></span>

Next, I set the derivative equal to zero in order to find the maximum point (I know that I can prove that it is actually a max point by taking the second derivative later)

<span><span><span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]=0</span><span><span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]=0</span></span><span><span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span></span><span><span>−3<span>x2</span>−4x+4=0</span><span>−3<span>x2</span>−4x+4=0</span></span>

so I got:

<span><span>x=−2orx=<span>23</span></span><span>x=−2orx=<span>23</span></span></span>

<span><span>x=−2</span><span>x=−2</span></span> wouldn't make sense so I chose <span><span>x=<span>23</span></span><span>x=<span>23</span></span></span> and plugged it back into my original formula for the area of this trapezoid but my answer doesn't seem to match any of the multiple choice solutions. Where did I go wrong?

calculus optimization
6 0
3 years ago
Read 2 more answers
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