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noname [10]
3 years ago
11

How can i do that problem

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0
Just write down the question dum dum
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What is the solution to ln (x2 - 16) = 0?
bogdanovich [222]
ANSWER

x = \pm \sqrt{17}
EXPLANATION

The given equation is

ln( {x}^{2} - 16) = 0

Take antilogarithm of both sides to base e.

{e}^{ ln( {x}^{2} - 16) } = {e}^{0}

This will simplify to

{x}^{2} - 16 = 1

Group like terms to obtain,

{x}^{2} = 1 + 16

{x}^{2} = 17

Take square root of both sides to get,

x = \pm \sqrt{17}
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Answer:

75%

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Step-by-step explanation:

A' would be at (0,-4)

B' would be at (-2,1)

C' would be at (-2,-3)

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