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Savatey [412]
3 years ago
6

Need the answer for numbers 4,8,and 12

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

9514 1404 393

Answer:

  4) -438.75

  8) 539.68

  12) 22.54

Step-by-step explanation:

Put the values in place of the corresponding variables and do the arithmetic.

__

4) 6xy = 6(-7 1/2)(9 3/4) = -6(7.5)(9.75) = -438.75

__

8) I = prt = $2442 × 0.085 × 2.6 = $539.68

__

12) I = prt = ($578)(0.0325)(1.2) = $22.54

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6x to the power of 2 + 7x to the power of 3 + 8x to the power of 5 + 9
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4 0
3 years ago
Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

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3 0
3 years ago
Fill in the blanks to rewrite the following statement with variables: Given any positive real number, there is a positive real n
sveticcg [70]

Answer:

a) there is s such that <u>r>s</u> and s is <u>positive</u>

b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r

Step-by-step explanation:

a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.

b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.

3 0
3 years ago
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mixer [17]

Answer:

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Step-by-step explanation:

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Using the quadratic formula

a = 1 b = 3 c = - 7

x =  \frac{3 ± \sqrt{ {3}^{2} - 4(1)( - 7) }  }{2(1)}  \\  x =  \frac{ - 3± \sqrt{9 + 28} }{2}  \\  \\ x =  \frac{ -3 ± \sqrt{37} }{2}  \\  \\ x =  \frac{ - 3 +  \sqrt{37} }{2}  \:  \:  \:  \:  \: or \:  \:  \: x =  \frac{ - 3 -  \sqrt{37} }{2}  \\  \\ x = 1.54 \:  \:  \: or \:  \: x =  - 4.54

Hope this helps you

7 0
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