<h2>
Miranda's rate is 12 hours per mies.</h2>
Step-by-step explanation:
Given by question,
Miranda began her ride from home merely that she was 50 miles away from home after 4 hours of riding.
To find, Miranda's rate = ?
2 hours later she was 974 miles from home.
∴ 2 hours she rode = 74 miles - 50 miles
Miranda rides 24 miles in 2 hours.
∴ Miranda rides in 1 hour = 
= 
Thus, Miranda's rate is 12 hours per mies.
Answer:
1. P= 80
60/.75=80
2. x= 5/3
-27/25x / -27/25= -9/5 / -27/25
-9/5 / -27/25 --- -9/5 x -25/27
3. -300
-2.7/-2.7 = 810/-2.7
4. 120
84x100/70
<u>84/x = 70/100</u>
Answer:
t2=15
t3=28
t4=41
first term (a)=2
common difference (d)=13
General terms tn=a+(n-1)d
Answer: See attached table
Step-by-step explanation:
![\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}](https://tex.z-dn.net/?f=%5Cbegin%7Btable%7D%5B%5D%5Cbegin%7Btabular%7D%7Blllll%7D%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%5Cend%7Btabular%7D%5Cend%7Btable%7D)
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
Answer:
0.74 to 6.06
Step-by-step explanation:
The groups are independnet,
SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61
At df=157, the t critical is 1.65
90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)
=(25.2-21.8)+-1.65*1.61
=0.74 to 6.06
