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yarga [219]
3 years ago
12

In the figure below, ∆ABC ~ ∆QRS.

Mathematics
2 answers:
Hatshy [7]3 years ago
8 0

Answer:

QR = 5

Step-by-step explanation:

It's given that ∆ABC ~ ∆QRS. As both of them are similar , the ratio of corresponding sides of both triangles will be proportional to each other.

\frac{AB}{QR}  =  \frac{BC}{RS}  =  \frac{AC}{QS}

AB = 50 ; AC = 60 ; QS = 6

From the above proportion ,

\frac{AB}{QR}=  \frac{AC}{QS}

Putting all the values ,

\frac{50}{QR}  =  \frac{60}{6}

=  >  \frac{50}{QR}  = 10

=  > QR =  \frac{50}{10}  = 5

sergiy2304 [10]3 years ago
5 0

QS/AC=6/60=1/10

QR/AB=QR/50=1/10

QR=5

SO THAT TRIANGLE ABC IS EQUAL TO TRIANGLE QRS(2SIDES PROPORTIONAL.INC. ANGLE)

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Step-by-step explanation:

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Step-by-step explanation:

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What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

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2 years ago
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