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IgorLugansk [536]
2 years ago
12

PLZ HELP AND EXPLAIN THIS PLZ

Mathematics
1 answer:
AURORKA [14]2 years ago
7 0

Answer:

A. <u>4</u> trucks will make $80 because 4 × 20 = 80, so they need to wash <u>38</u> cars to make the other $380 because 38 × 10 = 380.

($80 + $380 = $460)

B. <u>15</u> trucks will make $300 because

15 × 20 = 300, so they need to wash <u>16</u> cars to make the other $160 because 16 × 10 = 160. ($300 + $160 = $460)

C. <u>21</u> trucks will make $420 because

21 × 20 = 420, so they need to wash <u>4</u> cars to make the other $40 because 4 × 10 = 40.

($420 + $40 = $460)

D. <u>27</u> trucks will make $540, so they won't have to wash any cars because they would have already exceeded their goal of $460.

Not sure what to do for letter E. Sorry. I hope the rest makes sense though :)

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Answer:

a. 2,727

b. (85.6%, 87.6%)

Step-by-step explanation:

The percentage of the adults aged 57 through 85 that used at least one prescription medication = 86.6%

a. The expected number of the 3,149 subjects aged 57 through 85 that used at least one prescription medication = 3,149 × 86.6/100 = 2,727.034 ≈ 2,727 (subjects)

b. The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is given as follows;

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p} \cdot (1-\hat{p})}{n}}

Where;

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z = The z-value at 90% confidence level = 1.645

Therefore, we get the following confidence interval of the percentage of adults (rounded to one decimal place as required);

\left (0.866 - 1.645\times \sqrt{\dfrac{0.866 \times (1-0.866)}{3,149}}\right) \times  100 \%  \approx 85.6 \%

\left( 0.866 + 1.645\times \sqrt{\dfrac{0.866 \times (1-0.866)}{3,149}} \right) \times 100 \%  \approx 87.6 \%

The 90% confidence interval, of the percentage C.I. ≈ (85.6%, 87.6%).

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