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2 years ago

If I have three crackers and I ate one how many crackers do I have now?

Mathematics

1 answer:

ivanzaharov [21]2 years ago

5 0

If you have three crackers and eat one the answer is C.2

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Which ordered pair is generated from the equation shown below? y = 2x + 4 A. (1, 6) B. (1, 2) C. (3, 6) D. (8, 16)

USPshnik [31]

Answer:

The ordered pair generated from the equation is (1, 6).

Step-by-step explanation:

An ordered pair is a pair of numbers, representing two variables, in a specific order. For instance, (x, y) = (1, 2) here x = 1 and y = 2.

The equation provided is:

$y=2x+4$

Check for all the options:

A (1, 6): $y=2x+4\Rightarrow\ 6=(2\times 1) +4\Rightarrow\ 6=6$
B (1, 2): $y=2x+4\Rightarrow\ 2=(2\times 1) +4\Rightarrow\ 2\neq 6$
C (3, 6): $y=2x+4\Rightarrow\ 6=(2\times 3) +4\Rightarrow\ 6\neq10$
D (8, 16): $y=2x+4\Rightarrow\ 16=(2\times 8) +4\Rightarrow\ 16\neq20$

Thus, the ordered pair generated from the equation is (1, 6).

8 0

4 years ago

What geometric term describes a corner f a living room

murzikaleks [220]

The answer is a vertex. Corners of any shape are vertexes

5 0

3 years ago

P=3w^2. Calculate P when w=4.

algol13

P= 3(4)^2
P= 12^2
P = 144

4 0

3 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago

Find the solution of the system of equations. -7x+4y=-32 9x-2y=38

zlopas [31]

Answer:

(4,-1)

x=4

y=-1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers