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2 years ago

If I have three crackers and I ate one how many crackers do I have now?

Mathematics

1 answer:

ivanzaharov [21]2 years ago

5 0

If you have three crackers and eat one the answer is C.2

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The table below shows the total number of hours, Jessica, Emily, and Trina, each studied after given number of weeks. Part A one

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Answer:Y times X = 5

Step-by-step explanation:

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3 years ago

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Which number should be added to both sides of the equation to complete the square x^2-10x=7

mixer [17]

Answer:

Step-by-step explanation:

The number that needs to be added is the square of half the x-coefficient:

(-10/2)^2 = 25

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Adding that gives ...

(x -5)^2 = 32

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3 years ago

You know the length and width of a scale model. what additional information do you need to find the scale of the model?

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What the model is scaled by

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3 years ago

How many atoms of each elementare in the chemical formula NH.NOS?

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3 years ago

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Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

1 year ago