The volume (V) is given in terms of length (L), width (W), and height (H) by the formula ...
... V = LWH
Substituting your dimensions, you have
... V = (11.3 cm)·(18.9 cm)·(29 cm) = 6193.53 cm³ ≈ 6200 cm³
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The factor 29 cm has 2 significant digits, so that is the precision required of the answer. It could also be written with less ambiguity as to precision as 6.2 L. (Trailing zeros to the left of the decimal point are always ambiguous when it comes to significant digits.)
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
The diagonals bisect each other
Your solution would be x<25
Answer:
see below
Step-by-step explanation:
|x - 3| < 4
To remove the absolute values, we need to make two inequalities, one positive and one negative
x-3 < 4 and x-3 > -4
Add 3 to each side
x-3+3<4+3 and x-3+3 > -4+3
x<7 and x >-1
-1 <x <7
