All categories

3 years ago

In Khan Academy: Equations & inequalities word problems:

Mathematics

1 answer:

Leona [35]3 years ago

5 0

Answer ( if trying to find x ) :

x = 44

Step-by-step explanation:

5 x 7 = 35 ( area of picture )

120 -> ( area of the whole picture + frame )

120 - 35 = 85 ( area of just the frame )

factor's of 85 -> 1 ,5 ,17 ,85 ( can't be 1 by 85 inch's picture ,so you get 5 by 17 )

5 + 5 + 17 + 17 = 44 (perimeter of the frame ( perimeter formula= l + l + w + w ) )

44 inch's ( ? )

You might be interested in

If the cost of the framing material is $ 13 13 per linear foot and the cost of the pane glass is $ 24 24 per square foot, what i

miskamm [114]

I thank you should time 1313*2424==318.27

5 0

3 years ago

Find the complete factored form of the polynomial -24a6b4-40a3

Naddik [55]

For this case we have the following polynomial:

$-24a ^ 6b ^ 4-40a ^ 3$

We must find the greatest common factor of the terms of the polynomial.

The GCF of the coefficients is given by:

$24 = 3 * 8\\40 = 5 * 8$

Then we look for the GFC of the variables:

We have then:

$a ^ 6 = a ^ 3a ^ 3\\a ^ 3 = a ^ 3$

Finally rewriting we have: $-24a ^ 6b ^ 4-40a ^ 3 = -8a ^ 3 (3a ^ 3b ^ 4 + 5)$

Answer:

the complete factored form of the polynomial is:

$-8a ^ 3 (3a ^ 3b ^ 4 + 5)$

8 0

3 years ago

Give the digits in the ones place and the tenths place <br>23.91

Andru [333]

Answer:

Ones place: 3, Tenths place: 0.9

Step-by-step explanation:

Simple math

8 0

3 years ago

Help please!! Thanks :D

Marysya12 [62]

Answer:

i dont really know the answer

Step-by-step explanation:

5 0

3 years ago

Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean

kherson [118]

I believe the normal distribution is symmetrical above and below

the mean. That tells us that in this kind of distribution, the mean

and the median are the same number ... 50% of the population

is below it, and 50% is above it.

So if the female Labs' weight actually follows a 'normal' distribution

with a mean of 62.5 lbs, then 2,700 of them weigh more than 62.5 lbs

and 2,700 of them weigh less than that.

The standard deviation doesn't matter.

7 0

3 years ago