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Lerok [7]
3 years ago
8

A varies as a b if a =3, when b=24 find b when a=10

Mathematics
2 answers:
Bond [772]3 years ago
4 0

Answer:

B = 80            

Step-by-step explanation:

coldgirl [10]3 years ago
4 0

Answer:

b= 79.9= 80

Step-by-step explanation:

i hope this helps

sorry if it didn't help

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Please answer this question in the attachment below
Westkost [7]

Mark me brainliest if it helps you

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3 0
2 years ago
Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d)​, one of which is co
arlik [135]
A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

P(C) = \frac{1}{4}

The probability of choosing wrong answer is

P(W) = \frac{3}{4}

Using the multiplication rule
P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

WWC

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

WCW

Or the first one is correct and the last two are wrong. This will give the arrangement,

CWW
.

P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64}  \\ \\ P(One \: Correct) = \frac{27}{64}
7 0
4 years ago
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