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kvv77 [185]
2 years ago
7

Solve x-5y=-30, 3x+5y=10 show your work

Mathematics
1 answer:
marin [14]2 years ago
6 0

1) x = 5y - 30  

2) x = - 1.6y + 3.3

<em>im assuming these are 2 different questions</em>

<h3>Explanation:</h3><h3>1)</h3>

Start with the equation:

x - 5y= -30

add 5y to both sides:

x = 5y - 30

Your answer is x = 5y - 30  

<h3>2)</h3>

Start with the equation:

3x+5y=10

subtract 5y from both sides:

3x = -5y + 10

divide by 3 to get x singular

x = - 1.6y + 3.3

Your answer is x = - 1.6y + 3.3

Hope this helps :)

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If 5 bulbs are $24.95 how much money is 1 bulb?
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Answer:

4.99

Step-by-step explanation:

If you divide:

$24.95/5bulbs

you get

4.99/1 bulb  

5 0
3 years ago
Mr. Webster is buying a carpet for an exercise room in his basement the room will have an area of 230 ft.².
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Mr. Webster is buying a carpet for an exercise room in his basement the room will an area of 230 ft
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1. What is the prime factorization of 402? *<br> Your answer
docker41 [41]

Answer:

Step-by-step explanation:

Prime factorization requires dividing by primes starting with smallest prime number

402/2=201

201/3=67, 67 is prime so we cannot go further so the prime factorization of 402 is

2X3X67

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3 years ago
83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

5 0
2 years ago
After all your hard work studying for Algorithms you, Alice and Bob end up stuck in a room full of deadly zombies! Luckily you h
shutvik [7]

Answer:

The most important quantity to consider in order to answer this question is the arrival time of the zombies from their initial position, which is the quotient between their distance to the visitors, divided the zombie's speed.

See explanation below.

Step-by-step explanation:

Part 1)

What is crucial to know is what is the time at which each zombie would reach Alice and Bob, and that is given by the quotient between the distance away each zombie is, divided by the zombie's speed:

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Then, it is this quotient for each zombie, that one has to estimate given the input values distance and speed, and it is the output "time" (t_i) for each zombie, what we need to analyze so as to prioritize an order regarding which zombie to kill first.

Part 2)

Shooting the closest zombie first is not a good idea, since the speed of that closest zombie may be much slower than another zombie further away, but with much larger speed. Again, the important value to analyze is the time that it would take each zombie to reach Alice and Bob.

Part 3)

Shooting the fastest zombie first is not a good idea either, because that fastest zombie could be located very far away from the visitors, and other zombies closer by may reach them first.

Part 4)

The order that should be used to kill the zombies is given by the value of the time to reach Bob and Alice based on the quotient distance (di) over speed (si) explained in Part 1). The zombie that shows smallest time should be shot first, and then the others in increasing order of time value.

Part 5)

Notice that the individual zombie information is not presented in the question, but the student should be able to calculate the quotients for each zombie, and considering that there could be at most one shot every second, estimate the number of seconds that the time for each zombie in increasing order would allow until the addition of shooting time per second in the appropriate order cannot match the arrival time of the zombies that are left.

One should count number of seconds from the first shot (to the zombie with shortest arrival time), and then increase in one unit (one shot per second), to the following zombie with slightly larger arrival time), and so on, until the addition of seconds (one second per shot and per increasing arrival time of zombie) exceeds the next zombie arrival time.

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