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3 years ago

Please help me!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Romashka [77]3 years ago

5 0

This is an equation in the form of y = kx. Where y is the dependent variable, x is the independent variable, and k is the constant of proportionality.

In this case 7 would be your constant of proportionality
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What is the answer 12 x 12

aleksandr82 [10.1K]

12 × 12 would equal to 144

Hope this helped! :D

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3 years ago

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Every time Tom and Maya have a child, there is an equal probability of it being a boy or a girl.

cestrela7 [59]

All outcomes of three children (using G for girl and B for boy)
GGG, GGB,GBG,GBB,BGG,BGB,BBG,BBB
1) exactly two is 3 out of 8 total outcomes, or 3/8
2) all sons is one outcome, or 1/8

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3 years ago

Decimals from 7.0 to 8.4 with an interval of 0.2 between each pair of decimals

Vitek1552 [10]

Decimals from 7.0 to 8.4 with an interval of 0.2 between each pair of decimals

We start with 7.0 and keep adding 0.2 till we get 8.4

7.0 + 0.2 = 7.2

7.2 + 0.2 = 7.4

7.4 + 0.2 = 7.6

7.6 + 0.2 = 7.8

7.8 + 0.2 = 8.0

8.0 + 0.2 = 8.2

8.2 + 0.2 = 8.4

So, the decimals from 7.0 to 8.4 with an interval of 0.2 are

7.2, 7.4, 7.6, 7.8, 8.0, 8.2

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3 years ago

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Help me with 16,17,18,and 19 please simpl

mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

$\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\ \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\ \\=\dfrac{t^2-4t-3}{t^2+3t+18}$

Ques 17)

$\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\ \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}$

Ques 18)

Let the blank space be denoted by the quantity 'x'.

$\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2$

Ques 19)

Let the missing quantity be denoted by 'x'.

$\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9$

7 0

3 years ago

Please help me on this thank you so much

konstantin123 [22]

The answe is 32 over x

7 0

3 years ago