Answer:
note :
The equation of a linear function in point-slope form is y – y1 = m(x – x1)
The point is A (x1 , y1)
Step-by-step explanation:
in this exercice : y - 4 = 5 +(1/2)x
y - 4 = 0.5 ( x - 5/0.5)
y - 4 = 0.5( x - 10).....
note : the standard forme is : y = ax +b
in this exercice : y = (1/2)x+9
Answer:
points
Step-by-step explanation:
The value of x that makes m║n is 40°
<h3>Line of transverse on parallel lines: </h3>
In geometry, the line that intersects two straight lines at distinct points is known as a transversal.
<h3>Corresponding angles: </h3>
The angles that are formed when two parallel lines are intersected by a third line i.e a transversal are corresponding angles.
Note:
Two corresponding angles are formed by a transversal with two parallel lines that are equal
Here we have
The angle made by the intersecting line with line m is 120°
And the angle made by the same line with line n is 3x°
Let us assume that m║n
From above observations
The given angle are corresponding angles
=> 3x° = 120°
=> x° = 40°
Therefore,
The value of x that makes m║n is 40°
Learn more about the Line of transverse at
brainly.com/question/11592045
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Answer:
The football team drank a total of 75 gallons of water.
Step-by-step explanation:
Half of 50 gallons is 25 gallons. 25 gallons + 50 gallons = 75 gallons.
Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
