1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
2 years ago
15

Solve 7f + 6 = 27 show working out

Mathematics
2 answers:
amm18122 years ago
6 0

7f+6=27

7f=27-6

7f=21

Divide both sides by 7 to isolate f:

f=3

Hope this helps!

#HaveAnAmazingDay

GraceRosalia

scoray [572]2 years ago
3 0

Answer:

f = 3

Step-by-step explanation:

7f + 6 = 27 ( subtract 6 from both sides )

7f = 21 ( divide both sides by 7 )

f = 3

You might be interested in
Please help me quick ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
maria [59]
Area = (12ft)(4ft)
A = 48 ft^2
7 0
2 years ago
Write the equation of a line that is perpendicular to y = 5 y=5y, equals, 5 and that passes through the point ( − 7 , − 5 ) (−7,
Jlenok [28]
The line of the equation perpendicular to y=5 and cuts through (-5,-7) will be given by
m(x-x1)=y-y1
where m=slope.
from y=0x+5, the slope of the perpendicular line m=0,
thus the equation will be:
0(x--5)=y--7
0=y+7
y=-7
The equation is y=-7
3 0
3 years ago
Read 2 more answers
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
Roger has two dogs which are named Sparky and Cookie. The relationship of Sparky’s age, s, and Cookie’s age, c, can be represent
arlik [135]

Answer:

sparky 4 years older than cookie

Step-by-step explanation:

s=c+4

since there nothing to add or subtract. you are just gonna take that 4 and since there is a plus sign you are gonna say older than.

hope this helps

5 0
2 years ago
Read 2 more answers
F(x)=lx-2l-4 i need the range of this in interval notation,ASAP LIKE RIGHT THIS SECOND I WILL PUT YOU AS A BRAINLEST<3
kumpel [21]

Answer:

f = l + -2lx-1 + 3x-1

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • What is the answer to -5m-18=52
    8·1 answer
  • What is two expressions where the solution is 19
    11·1 answer
  • Which of the following would most likely measure about 4 meters ?
    5·1 answer
  • What are the possible rational zeros of f(x) = x4 + 2x3 − 3x2 − 4x + 12?
    7·2 answers
  • Which statement is true about the value of |-5|
    12·2 answers
  • A company sells cookies in 250-gram packs. When a particular batch of 1,000 packs was weighed, the mean weight per pack was 255
    5·1 answer
  • Two variables are correlated with r = -0.925<br><br> Which best describes....see photo
    8·1 answer
  • The width of a plastic storage bin is 4ft longer than the height. The length is 6ft longer than the height. The volume is 96 cub
    6·1 answer
  • 2) The equation y = 18x represents the relationship between 2, the number of hours biked, and
    12·2 answers
  • 30 points for RIGHT ANSWER
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!