Please help Consider: A (-3,-4), B (5,2), C (11,-6) What is AB? What is BC?

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

7 0

Answer:

AB = 10, BC = 10

Step-by-step explanation:

AB = length of segment AB = sqrt( (-3-5)^2 + (-4-2)^2 ) = sqrt( 64 + 36) = sqrt(100) = 10

BC = sqrt( (5-11)^2 + (2-(-6))^2 ) = sqrt( 36 + 64 ) = sqrt( 100 ) = 10

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Scott and Harry went cycling every day. They increased the number of minutes of cycling every week as described below:

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Answer:

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Step-by-step explanation:

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On, the other hand, harry cycled for 10 minutes in first week, 20 minutes in second, 40 minutes in third and 80 minutes in fourth week in which there is no consistency in the timings according to the weeks. Therefore, only, scott's method is linear as the number of minutes increased by an equal factor every week.

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-x^2+4x-8 <br>axis of symmerty

V125BC [204]

Answer:

$\boxed {\boxed {\sf x=2}}$

Step-by-step explanation:

The axis of symmetry can be calculated using the formula:

$x=\frac{-b}{2a}$

First we must determine a and b from the quadratic: $-x^2+4x-8$ . This is in standard form, with the highest power first in descending order.

Standard form is also: $ax^2+bx+c$

If we compare this to the quadratic given, we can conclude that:

$a= -1 \\b= 4 \\c= -8$

Substitute the values for a and b into the formula.

$x= \frac{-(4)}{2(-1)}$

Multiply in the denominator.

$x=\frac {-4}{-2}$

Divide.

$x=2$

This can also be determined from the graph. It is the x-coordinate of the vertex or the maximum/minimum. It divides the quadratic into 2 symmetrical halves.