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3 years ago

Please help Consider: A (-3,-4), B (5,2), C (11,-6) What is AB? What is BC?

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

7 0

Answer:

AB = 10, BC = 10

Step-by-step explanation:

AB = length of segment AB = sqrt( (-3-5)^2 + (-4-2)^2 ) = sqrt( 64 + 36) = sqrt(100) = 10

BC = sqrt( (5-11)^2 + (2-(-6))^2 ) = sqrt( 36 + 64 ) = sqrt( 100 ) = 10

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There are 33 students in a school chorus. The ratio of boys to girls is 5:6 How many girls are in the school chorus?

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The vertices of ΔGHI are G (2, 4), H (4, 8), and I (8, 4). The vertices of ΔJKL are J (1, 1), K (2, 3), and L (4, 1). Which conc

Klio2033 [76]

Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

The first step is finding the sides of each triangle.

In triangle GHI, we have that:

GH = sqrt((4-2)^2 + (8-4)^2) = 4.4721

HI = sqrt((8-4)^2 + (4-8)^2) = 5.6569

IG = sqrt((2-8)^2 + (4-4)^2) = 6

Now, for the triangle JKL, we have:

JK = sqrt((2-1)^2 + (3-1)^2) = 2.2361

KL = sqrt((4-2)^2 + (1-3)^2) = 2.8284

LJ = sqrt((1-4)^2 + (1-1)^2) = 3

The triangles are not congruent, because the sides are different

They are similar, because their sides have a proportion (sides of GHI are 2 times the sides of JKL). If they are similar, they have the same angles.

The ratio of their corresponding sides is 1:2, not 1:3

The ratio of their corresponding angles is 1:1, not 1:3

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3 years ago

What is an equation of the line that passes through the points (0, 3) and (5,-3)?

Arisa [49]

Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

$y = m\cdot x + b$ (Eq. 1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $(x_{1},y_{1}) = (0,3)$ and $(x_{2},y_{2})=(5,-3)$ , the following system of linear equations is constructed:

$b = 3$ (Eq. 2)

$5\cdot m + b = -3$ (Eq. 3)

The solution of the system is: $b = 3$ , $m = -\frac{6}{5}$ . Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

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3 years ago