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son4ous [18]
3 years ago
14

(Multiple choice)

Mathematics
1 answer:
spayn [35]3 years ago
5 0
I believe the answer is A
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Lines a, b, c, and d Intersect as shown.
Mnenie [13.5K]

Answer:

95 is the answer I took the test

8 0
3 years ago
Yolanda watches a carnival game in which a paper cup is tossed. It costs $1 to play the game. If the cup lands upright, the play
a_sh-v [17]
Yolanda only wins if the cup lands upright.
From the experimental data we see that the probability of winning is 5 out of 50, or 10%. Therefore, if Yolanda plays 10 times she can expect to win 10% of 10 times = 1 time. She will lose 9 times.
8 0
4 years ago
Read 2 more answers
Which inequality is graphed below?
krok68 [10]

ANSWER

y  \geqslant  \frac{1}{4} x - 1

EXPLANATION

The graph has a solid boundary line.

The region above the boundary line is shaded

Therefore the inequality sign involved is '≥'

The boundary line has equation

y =  \frac{1}{4} x - 1

We can now conclude that, the inequality graphed above is

y  \geqslant  \frac{1}{4} x - 1

7 0
3 years ago
Read 2 more answers
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
djyliett [7]

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             10 s * \frac{min}{60 s}  = \frac{1}{6} min

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

   

7 0
4 years ago
Find the sum of the first 100 terms in the series
iVinArrow [24]
Hello,

\dfrac{1}{n} - \dfrac{1}{n+1} = \dfrac{1}{n(n+1)} \\&#10;&#10; \dfrac{1}{1*2} = \dfrac{1}{1} - \dfrac{1}{2} \\&#10;&#10; \dfrac{1}{2*3} = \dfrac{1}{2} - \dfrac{1}{3} \\&#10;&#10; \dfrac{1}{3*4} = \dfrac{1}{3} - \frac{1}{4} \\&#10;&#10;...\\&#10; \dfrac{1}{n*(n+1)} = \dfrac{1}{n} - \dfrac{1}{n+1} \\&#10;&#10;&#10;&#10;

Adding member by member, we have

\dfrac{1}{1*2} + \dfrac{1}{2*3} +\dfrac{1}{3*4} +...\dfrac{1}{n*(n+1)}=\\&#10; &#10;\dfrac{1}{1}  - \dfrac{1}{n+1} \\&#10;&#10;= \dfrac{n}{n+1} \\&#10;&#10;

if n=100 sum \boxed{= \dfrac{100}{101} }


3 0
3 years ago
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