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andreev551 [17]
2 years ago
14

Helpppppp meeee!!!!!!!

Mathematics
1 answer:
zysi [14]2 years ago
8 0

Answer:

IT>RT>RI

Step-by-step explanation:

sin72°>sin67°>sin41°

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(URGENT, IN THE MIDDLE OF A QUIZ!)<br> (Math)
Sauron [17]

Answer: D

Step-by-step explanation:

The pythagorean theorem shows that a^{2} +b^2= c^2.

This shows that the two shaded squares are equal, so D is incorrect.

5 0
3 years ago
Katy invests a total of $13,000 in two accounts paying 2% and 7% annual interest, respectively. How much was invested in each ac
kherson [118]

Answer:

2 % amount = 12000     7% amount = 1000 dollars

Step-by-step explanation:

x = 2% amount

 then  13 000 - x  = 7% amount

.02x   + .07 (13000-x)  = 310

-.05x + 910 = 310

.05x = 600

x = 600/.05 = 12000      then the 7% amount is 1000

4 0
1 year ago
An amount of $350,000 is borrowed for a period of 30 years at an interest rate of 5.5%. The amortization schedule for this
Annette [7]
350,000 . 250,00 . 1,987.26
8 0
2 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
Find the area of the triangle with vertices: q(3,-4,-5), r(4,-1,-4), s(3,-5,-6).
maw [93]

Answer:

  (√6)/2 square units

Step-by-step explanation:

The area of a triangle is half the magnitude of the cross product of the vectors representing adjacent sides.

  QR = (4-3, -1-(-4), -4-(-5)) = (1, 3, 1)

  QS = (3 -3, -5-(-4), -6-(-5)) = (0, -1, -1)

The cross product is the determinant ...

\text{det}\left|\begin{array}{ccc}i&j&k\\1&3&1\\0&-1&-1\end{array}\right|=-2i+j-k

The magnitude of this is ...

  |QR × QS| = √((-2)² +1² +(-1)²) = √6

The area of the triangle is half this value:

  Area = (1/2)√6 . . . . square units

3 0
3 years ago
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