Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer: 72
Step-by-step explanation:
If all the sandwiches will have a slice of cheese, you just need to add up all of the sandwiches order (28 + 14 + 30 = 72)
Yes, it makes sense to represent the relationship between the amount saved and the number of months with one constant rate. The relationship is 35x+ 100.
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Relationship between the amount saved and the number of months</h3>
After 1 month, Jane will saved=$35+$100
After 1 month, Jane has saved=$135
Hence,
Let x represent the number of months
Since every month she saved $35 which inturn means that in x number of months she can save 35x. Based on this the relationship between the amount saved and the number of months is 35x +100.
Therefore it makes sense to represent the relationship between the amount saved and the number of months with one constant rate. The relationship is 35x+ 100.
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There are 31+42+50+61=184 total females, and 50+61=111 females in grades 11 and 12, so the percentage is 111/184*100=60.33 percent, which can be rounded to 60%.
