Answer:
(4,-1)
x=4
y=-1
Step-by-step explanation:
Answer:
Your equation is 
Step-by-step explanation:
Well, the center origin of the circle is given (h,k) = (1,-1).
We have to find our radius as they gave us a point. from origin to the edge of the circle.
Using the formula: (x - h)^2 + (y - k)^2 = r^2
Plug in our (h,k) = (1,-1) and (x,y) = (0.5,-1) to solve for radius.
(x - h)^2 + (y - k)^2 = r^2
(0.5 - (1))^2 + (-1 - (-1))^2 = r^2
(-0.5)^2 + (0)^2 = r^2
1/4= r^2
r^2 = 1/4
r = 1/2
We can use the points (-4, 3) and (3, 1) to solve.
Slope formula: y2-y1/x2-x1
1-3/3-(-4)
-2/7
Therefore, the answer is C
Best of Luck!
Answer:
2(xy + 2)(x + 1) (C)
Step-by-step explanation:
2x^2y + 2xy + 4x + 4
= 2xy(x + 1) + 4(x + 1)
= (2xy + 4)(x + 1)
= 2(xy + 2)(x + 1)
Answer: cos(x)
Step-by-step explanation:
We have
sin ( x + y ) = sin(x)*cos(y) + cos(x)*sin(y) (1) and
cos ( x + y ) = cos(x)*cos(y) - sin(x)*sin(y) (2)
From eq. (1)
if x = y
sin ( x + x ) = sin(x)*cos(x) + cos(x)*sin(x) ⇒ sin(2x) = 2sin(x)cos(x)
From eq. 2
If x = y
cos ( x + x ) = cos(x)*cos(x) - sin(x)*sin(x) ⇒ cos²(x) - sin²(x)
cos (2x) = cos²(x) - sin²(x)
Hence:The expression:
cos(2x) cos(x) + sin(2x) sin(x) (3)
Subtition of sin(2x) and cos(2x) in eq. 3
[cos²(x)-sin²(x)]*cos(x) + [(2sen(x)cos(x)]*sin(x)
and operating
cos³(x) - sin²(x)cos(x) + 2sin²(x)cos(x) = cos³(x) + sin²(x)cos(x)
cos (x) [ cos²(x) + sin²(x) ] = cos(x)
since cos²(x) + sin²(x) = 1
