If you roll two fair dice, a green one and a red one?
A= are the outcomes on the dice independent?
B= Find P(1 on green die and 2 on red die)
C= Find P(2 on green die and 1 on red die)
D= Find P(1 on green die and 2 on red die) or (2 on green die and 1 on red die)
A= yes
B= p(1)*(p2)=1/6*1/6=1/36
C= p(2)*(p1)=1/36
D= 1/36=1/18 I hope it helps !
Answer:
16/33
Step-by-step explanation:
We have a bag of :
9 red marbles
6 blue marbles
7 green marbles
11 yellow marbles
Total number of marbles = 33 marbles.
The possibility that a red or green marble will be selected from a bag
P( Red or Green) = P(Red) + P(Green)
In the question we are not told if it is with replacement or without. We do both
With replacement
P( R or G) = P(Red) + P(Green)
P(Red)= 9/33
P(Green) = 7/33
= 9/33 + 7/33
= 16/33
Therefore, the possibility that a red or green marble will be selected from a bag is 16/33
Arithmetic sequences have a common difference between consecutive terms.
Geometric sequences have a common ratio between consecutive terms.
Let's compute the differences and ratios between consecutive terms:
Differences:
Ratios:
So, as you can see, the differences between consecutive terms are constant, whereas ratios vary.
So, this is an arithmetic sequence.
Step-by-step explanation:
L.H.S=(1-cosB)(1+cosB)
=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}
=sin^2B
=1/cosec^2B
Therefore,L.H.S=R.H.S proved
