1. The probability that your mail is delivered before 2 pm is 0.9, so the probability that the mail is delivered at 2 pm or after 2 pm (so not before 2 pm) is 1-0.9=0.1.

Remark: 0.9=9/10=90/100=90%, and 0.1 is 10%

2. Probability of the mail being delivered before 2 pm for 2 consecutive days is

3. take a look at the picture attached, the tree diagram is another method we could use.

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^

marta [7]

Answer:

$-\frac{5}{4x}$

Step-by-step explanation:

<h2> $\left(-5x^3\right)^3\div \left(10x^5\right)^2$ </h2><h2> $\frac{-5^3x^9}{\left(10x^5\right)^2}$ </h2><h2> $\frac{-5^3x^9}{10^2x^{10}}$ </h2><h2> $\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}$ </h2><h2> $\frac{-5x^9}{2^2x^{10}}$ </h2><h2> $\frac{-5}{2^2x}$ </h2>

$-\frac{5}{4x}$

- hope it helps! -

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3 0

1 year ago

Given h(x) = -x + 5, find h(-5).

Murrr4er [49]

Answer:

Step-by-step explanation:

h(x) = -(-5) + 5

h(x) = 5 + 5

h(x) = 10

3 0

2 years ago

Given that y varies directly with x and y = 42 when x = 14, find y when x =90.

Anvisha [2.4K]

Direct Variation equation: y=kx, k=y/x
42/14=3
k=3
y=3x
y=3(90)
y=270

3 0

3 years ago