Will mark as brainliest plz helpp

Mathematics

1 answer:

almond37 [142]3 years ago

4 0

x - √3y - 4 = 0 → Choice A

Step-by-step explanation:

x - 4 = √3y

x - 4 - √3y = √3y - √3y

x - 4 - √3y = 0

x - √3y - 4 = 0

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Find the equation of a line passing through the point(-3,0) and (2,-3)

Svetradugi [14.3K]

Answer (assuming the question allows it to be written in slope-intercept form):

$y = -\frac{3}{5} x-\frac{9}{5}$

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ , substitute the given points' x and y values, and simplify:

$m = \frac{(-3)-(0)}{(2)-(-3)} \\m =\frac{-3-0}{2+3}\\m = -\frac{3}{5}$

Thus, the slope is $-\frac{3}{5}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ and substitute real values for $m$ , $x_1$ , and $y_1$ .

Since $m$ represents the slope, substitute $-\frac{3}{5}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

$y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}$