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2 years ago

7. Convert the subtraction problem into an addition problem. 10- (-5)

Mathematics

1 answer:

dalvyx [7]2 years ago

7 0

Answer:

10 + 5

Step-by-step explanation:

If you are subtracting a negative then it become adding a positive. A way to remember this is because it has matching socks.

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8n + 12 - 5n = 21 n=?

insens350 [35]

Answer:

n=3

Step-by-step explanation:

Simplifying

8n + 12 + -5n = 21

Reorder the terms:

12 + 8n + -5n = 21

Combine like terms: 8n + -5n = 3n

12 + 3n = 21

Solving

12 + 3n = 21

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.

12 + -12 + 3n = 21 + -12

Combine like terms: 12 + -12 = 0

0 + 3n = 21 + -12

3n = 21 + -12

Combine like terms: 21 + -12 = 9

3n = 9

Divide each side by '3'.

n = 3

Simplifying

n = 3

5 0

3 years ago

Read 2 more answers

In 3 and 4, Classify each triangle by its sides and then by its angles

romanna [79]

Answer:

3. Sides: Equilateral

Angles: Acute

4. Sides: Isosceles

Angles: Right

Step-by-step explanation:

3. Sides: Equilateral because in an equilateral triangle all sides are equal.

Angles: Acute because in an acute triangle all angles are acute.

4. Sides: Isosceles because in an isosceles triangle two legs are equal.

Angles: Right because in a right triangle, one angle is right.

7 0

2 years ago

Find the greatest common factor of 210, 84, and 56

mr Goodwill [35]

To get the Greates Common Factor (GCF) of 84 and 210 we need to factor each value first and then we choose all the copies of factors and multiply them:

84: 223 7210: 2 357GCF: 2 3 7

The Greates Common Factor (GCF) is: 2 x 3 x 7 = 42

3 0

2 years ago

Read 2 more answers

Which mathematical term describes both 19x and 4x in the expression 19x+4x?

Phoenix [80]

Answer:

The answers is coefficient

Step-by-step explanation:

they both have a variable attached which makes them both coefficients

8 0

2 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

2 years ago