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Ksivusya [100]
3 years ago
7

What is the area of the shaded region?

Mathematics
2 answers:
pochemuha3 years ago
5 0

Answer:

236

Step-by-step explanation:

19x15 = 285sq. inc.

7x7 = 49 sq. inc.

285-49 = 236sq. inch

Travka [436]3 years ago
5 0

Answer:

big area

19 x 15= 285 in^2

small area

7 x7 = 49 in^2

subtract

285-49 =236 in^2

answer is 236

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What is the answer 2( 4.8j + 4.57 ) ≤ - 19.06 – 18.6j
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A rectangular garden is to be fenced so that one of the sides is 5 feet longer than an adjacent side (s). Which of the following
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3 0
3 years ago
I don’t understand this someone pls help me! (Question 10)
Likurg_2 [28]

Answer:

  a. f(n) = n(n+1)/2

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Step-by-step explanation:

a. The terms are 1, 3, 6, 10, ...

Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.

When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.

For the polynomial ...

  f(n)=an^2+bn+c

We can substitute values for n and f(n) to get 3 equations in 3 unknowns:

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Solving these equations by your favorite method gives ...

  (a, b, c) = (1/2, 1/2, 0)

That is, the function representing the relationship is ...

  f(n) = n(n+1)/2 . . . . the function describing the relationship

__

b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26

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  n(n +1)/2 = 190

  n(n +1) = 380 = 19(20)

The 19th term will have 190 squares.

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d. Terms 5 and 6 are 15 and 21.

17 is not the value of one of the terms in this sequence.

6 0
3 years ago
Please help me do the substitution for this problem and the check thank you
Alexxandr [17]
(-2,0) instead of substitution, you can use elimination which the 3x's will cancel out and you solve the system regularly
8 0
3 years ago
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