.125 would be 8 as a whole number
Answer:
A consumer organization estimates that over a 1-year period 16% of cars will need to be repaired once, 9% will need repairs twice, and 3% will require three or more repairs..
We have the cars that do not need repair =
%
(16+9+3=28% cars need repair of some sort)
What is the probability that :
a) neither will need repair?
=> 
b) both will need repair?
=>
c) at least one car will need repair?
=> 
=> 
Answer:
Step-by-step explanation:
2(x + 15)⁰ + (3x + 20)⁰=180⁰
2x + 30⁰ + 3x + 20⁰=180⁰
2x + 3x + 30⁰ + 20⁰=180⁰
5x + 50⁰ - 50⁰=180⁰-50⁰
5x=130⁰
5x/5=130⁰/5
x=26⁰
The answer to that question is that the correct answer is 3.
Answer:
∠CBA
Step-by-step explanation: