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Solnce55 [7]
3 years ago
13

Which relation is a function?

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
It should be the second or forth one, a function can’t have the same input, which is x (x,y) so its the second or forth option.
Gemiola [76]3 years ago
7 0

Answer:

{(5,0), (-8,-5), (-8, 5), (-5, -8)} I think this would be the answer

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A round mirror has a circumference of 87.92 inches. Calculate the area of the mirror.
Zarrin [17]

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=87.92 \end{cases}\implies 87.92=2\pi r\implies \cfrac{87.92}{2\pi }=\boxed{r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~\hspace{7em}A=\pi \left( \boxed{\frac{87.92}{2\pi }} \right)^2 \\\\\\ A=\pi \cdot \cfrac{87.92^2}{4\pi^2}\implies A=\cfrac{87.92^2}{4\pi }\implies A\approx 615.127998

6 0
3 years ago
What the answer question
Ilya [14]

Answer:

<h2>Surface area = 373.66</h2><h2>Step-by-step explanation:</h2>

T.S.A = \pi r(r+l)\\l = 10mm\\r = 7mm\\\\T.S.A = 3.14 \times 7(7 + 10)\\= 21.98(17)\\T.S.A = 373.66\\\\T.S.A =  373.66

3 0
3 years ago
One hundred sixty divided by one fourth equals what
DerKrebs [107]
0.0015625 is what I got
6 0
4 years ago
Which point is the vertex of the quadratic function f(x)=x2−6x+8?
olya-2409 [2.1K]
(3,-1)
It needs to be written in standard form before you try to solve it.

4 0
4 years ago
Read 2 more answers
Can u help me pls they are exponents with multiplication and division
Ronch [10]
When there is a multiplication involving exponents, we need to evaluate the numbers and each variables separately. In this case, we have 5 and 4 as the numbers, and w and h for the variables.

When we multiply 5 and 4 we get:
5 \times 4 = 20

For w, we have {w}^{6}, {w}^{4}, w. While we are multiplying the w's, we need to add the exponents together to get the final answer: {w}^{6} \times {w}^{4} \times w = {w}^{11}

For h's, there are {h}^{2}, {h}^{5}, {h}^{4}. When we apply the same thing to h's, we get {h}^{2} \times {h}^{5} \times {h}^{4} = {h}^{11}

For the final step, we need to write all of these together: 20 \times {w}^{11} \times {h}^{11} \: \: or \: \: 20 {w}^{11} {h}^{11} \: \: or \: \: 20 {(wh)}^{11}
3 0
4 years ago
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