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marissa [1.9K]
3 years ago
9

Please help me with this

Mathematics
1 answer:
Sav [38]3 years ago
6 0

Answer:

Step-by-step explanation:

Start with the distance squared.

The distance from the center to the point on the circle is found from

Formula

d^2 = r^2 = (x2 - x1)^2 + (y2 - y1)^2

Givens

x2 = 2

x1 = - 5

y2 = -8

y1 = - 8

Center= (-5,-8)

Solution

r^2 = (2 - - 5)^2 + (-8 - - 8)^2

r^2 = 49 + 0

r^2 = 49

equation

(x + 5)^2 + (y + 8)^ = 49

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Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8
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\sqrt{(x-0)^{2}+(y-8)^{2}}

Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, y=c, is: |y-c|. Since our directrix is y=-8, the distance to our point will be:
|y-(-8)|
|y+8|

Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
\sqrt{(x-0)^{2}+(y-8)^{2}}=|y+8|
(\sqrt{(x-0)^{2}+(y-8)^{2}})^{2}=|y+8|^{2}
(x-0)^{2}+(y-8)^{2}=y+8

Finally, we can expand and solve for y:
x^2+y^2-16y+64=y^2+16y+64
x^{2}-16y=16y
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y= \frac{1}{32} x^2

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3 0
3 years ago
Several children are standing in line to ride a roller coaster. Their heights, in inches, are 59, 68, 58, 65, 62, 68, 67. What i
Brrunno [24]
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8 0
4 years ago
The frequency table shows the results of tossing a number cube 50 times. Which statement
Paul [167]

Answer:

Option (1) is the correct option.

Step-by-step explanation:

From the given frequency table,

Option (1).

Tossing an even number is more likely than tossing an odd number.

Frequencies of tossing even numbers 2, 4, 6 = 10, 10, 9

Frequencies of tossing odd numbers 1, 3, 5 = 8, 6, 7

Which shows frequencies of tossing even numbers are more.

Therefore, Option (1) is correct.

Option (2)

The number 2 will be the next number tossed.

Since it is unpredictable, therefore, this option is incorrect.

Option (3)

Number 4 is half as likely to be tossed as the number 3.

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Frequency of tossing 4 = 10

Frequency of tossing 3 is not the half of tossing 4.

Therefore, Option (3) is incorrect.

Option (4)

Probability of tossing the number 2 = \frac{\text{Frequency of tossing 2}}{\text{Total frequency}}

                                                           = \frac{10}{8+10+6+10+7+9}

                                                           = \frac{10}{50}

                                                           = \frac{1}{5}

Therefore, option (4) is incorrect.

3 0
3 years ago
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