1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Viktor [21]
3 years ago
13

Helpppppppp Write a linear function f(x) with the values f(3) = -1 and f(6) = 1.

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0
The Answers hope this helps

You might be interested in
What would be the volume of a box that is 6 1/2 inches tall 5 inches across the bottom and top and 1 cm width.
ss7ja [257]

Answer:

Volume calculator helps you find the volume of common ... The volume calculator will calculate the volume of some of the most ... cubic inches, 1, 5.79 10-4, 2.1 10-5, 4.3 10-3, 3.7 10-3, 3.6 10-3, 10-4 ... Rectangular solid (volume of a box) = lwh , where l is the length, w is the width and h is the height (a ...

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can somebody help me out
Alex_Xolod [135]
First one is C (18 sq units)

Second one is A (12sq2 units)
7 0
3 years ago
Please help!!<br> Write a matrix representing the system of equations
frozen [14]

Answer:

(4, -1, 3)

Step-by-step explanation:

We have the system of equations:

\left\{        \begin{array}{ll}            x+2y+z =5 \\    2x-y+2z=15\\3x+y-z=8        \end{array}    \right.

We can convert this to a matrix. In order to convert a triple system of equations to matrix, we can use the following format:

\begin{bmatrix}x_1& y_1& z_1&c_1\\x_2 & y_2 & z_2&c_2\\x_3&y_2&z_3&c_3 \end{bmatrix}

Importantly, make sure the coefficients of each variable align vertically, and that each equation aligns horizontally.

In order to solve this matrix and the system, we will have to convert this to the reduced row-echelon form, namely:

\begin{bmatrix}1 & 0& 0&x\\0 & 1 & 0&y\\0&0&1&z \end{bmatrix}

Where the (x, y, z) is our solution set.

Reducing:

With our system, we will have the following matrix:

\begin{bmatrix}1 & 2& 1&5\\2 & -1 & 2&15\\3&1&-1&8 \end{bmatrix}

What we should begin by doing is too see how we can change each row to the reduced-form.

Notice that R₁ and R₂ are rather similar. In fact, we can cancel out the 1s in R₂. To do so, we can add R₂ to -2(R₁). This gives us:

\begin{bmatrix}1 & 2& 1&5\\2+(-2) & -1+(-4) & 2+(-2)&15+(-10) \\3&1&-1&8 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\0 & -5 & 0&5 \\3&1&-1&8 \end{bmatrix}

Now, we can multiply R₂ by -1/5. This yields:

\begin{bmatrix}1 & 2& 1&5\\ -\frac{1}{5}(0) & -\frac{1}{5}(-5) & -\frac{1}{5}(0)& -\frac{1}{5}(5) \\3&1&-1&8 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\3&1&-1&8 \end{bmatrix}

From here, we can eliminate the 3 in R₃ by adding it to -3(R₁). This yields:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\3+(-3)&1+(-6)&-1+(-3)&8+(-15) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&-5&-4&-7 \end{bmatrix}

We can eliminate the -5 in R₃ by adding 5(R₂). This yields:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0+(0)&-5+(5)&-4+(0)&-7+(-5) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&0&-4&-12 \end{bmatrix}

We can now reduce R₃ by multiply it by -1/4:

\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\ -\frac{1}{4}(0)&-\frac{1}{4}(0)&-\frac{1}{4}(-4)&-\frac{1}{4}(-12) \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 2& 1&5\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

Finally, we just have to reduce R₁. Let's eliminate the 2 first. We can do that by adding -2(R₂). So:

\begin{bmatrix}1+(0) & 2+(-2)& 1+(0)&5+(-(-2))\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 0& 1&7\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

And finally, we can eliminate the second 1 by adding -(R₃):

\begin{bmatrix}1 +(0)& 0+(0)& 1+(-1)&7+(-3)\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}\\\Rightarrow\begin{bmatrix}1 & 0& 0&4\\ 0 & 1 & 0& -1 \\0&0&1&3 \end{bmatrix}

Therefore, our solution set is (4, -1, 3)

And we're done!

3 0
3 years ago
Britney has 50 beds 70% of the beds are gold how many beds are gold
belka [17]

Answer:

35 beds

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
50 POINTS NO JOKE IM DYING I NEED HELP
Effectus [21]

Answer:

9 x 7 = 63 is cost of 9 people

3 x 9

6 x 8

8 x 8

9 x 7

3 0
3 years ago
Other questions:
  • The chances of winning are often written in terms of odds rather than probabilities. The odds of winning is the ratio of the num
    7·1 answer
  • Two triangular roofs are similar. The ratio of the corresponding sides of these roofs is 2:3. If the altitude of the bigger roof
    6·1 answer
  • Solve y=3x-7 and 4x+3y=18 by substitution
    14·2 answers
  • Find the 50th term sequence 5 , -2 , -9 , -16
    6·2 answers
  • Nick was thinking of a number. Nick halves it and gets an answer of 39.5. What was the original number?
    9·2 answers
  • How do u solve it, I'm stuck please help.
    6·2 answers
  • Question 2/11 i’ll mark brainliest
    9·1 answer
  • What is a factor of 42
    14·2 answers
  • Learn with an example
    14·1 answer
  • Finish the sequence of 10 numbers 2,27,52
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!