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belka [17]
3 years ago
15

Giving Brainliestttttttt to first answer that’s correct!

Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

I think C sorry if wrong

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What is the solution to the function f(x)=x^2(x-2)^2 when x=2
Alecsey [184]

Answer:

when x=2 then the answer is given by the function

f(x)=2^2(2-2)^2=4

3 0
3 years ago
Four percent of the welds on an automobile assembly line are defective. The defective welds are found using an X-ray machine. Th
Helga [31]

Answer:

a ) See Annex

b) P₁  =  0,0464       or    P₁  =  4,64 %

c) P₄  = 0,92   or   P₄  = 92 %

Step-by-step explanation:

b) P₁ [ X being defective ]  =  P₂   +   P₃

Where P₂  is the probability of X rays machine detects a weld defective and the weld is really defective

And  P₃  is the probability of X rays machine detects a weld defective and the weld is not defective

Then

P₂  =  0,04 *  0,92  =  0,0368

P₃  =  0,96 * 0,01  = 0,0096

Then  P₁  =  0,0368  +  0,0096

P₁  =  0,0464       or    P₁  =  4,64 %

c) P₄ = 0,04 *0,92

P₄  = 0,92   or   P₄  = 92 %

7 0
3 years ago
Anna wants to factor the polynomial p(x)=5x^4+40x. She knows that the sum of cubes formula is a^3+b^3=(a+b)(a^2−ab+b^2).
Artemon [7]

Answer:

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

Step-by-step explanation:

p(x) = 5x^4 + 40x

p(x) = 5x(x^3 + 8)

p(x) = 5x(x + 2)(x^2 - 2x + 4)

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

7 0
3 years ago
Help...........................
Ksivusya [100]

Answer:

me

Step-by-step explanation:

pleas i'm begging you

5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
3 years ago
Read 2 more answers
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