This cannot be the question. You definitely read this wrong. If p(notA)= .75 then P(not A) = .75...
If the question is find P(A), however, then the use the compliment rule
1- P(not A) = P(A)
1-.75 = .25
Answer:
Step-by-step explanation:
Area: 28.26
Circumference: 12.56
Here is the solution of the given problem above.
Bucket A: dumps every 16 minutes
Bucket B: dumps every 14 minutes
Last time they both dump water: 3:20p.m.
The first thing we need to do is to find the LCM.
14 and 16 / 2 = 7 and 8.
LCM: 2x7x8 = 112 minutes from the last time and this is equivalent to 1 hour and 52 minutes. So 3: 20 p.m + 1: 52 p.m = 4: 72
since there are only 60 minutes in an hour, the result would be 5: 12P.M.
So the first time that they dump water is at 5:12 P.M
Next, 5: 12 p.m + 1 hour and 52 minutes is 6:64 which gives us 7:04 pm. Therefore, the next two times that both buckets dump water at the same time are 5:12 P.M and 7:04 P.M. Hope this answer helps.
Answer: x = 18
explanation: the two angles are congruent bc so you can set the equation up as 9x - 40 = 5x + 32 and then solve for x
hope this helps :)
Hello,
Please, see the attached file.
Thanks.
