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icang [17]
2 years ago
8

The sum of 10 numbers are 550. find their average number.​

Mathematics
2 answers:
Anika [276]2 years ago
3 0

Answer:

55

Step-by-step explanation:

550/10 = 55

Black_prince [1.1K]2 years ago
3 0

Answer:

Average number will be 55

Step-by-step explanation:

Average number

=  \frac{550}{10}

= 55

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To solve the equation X - 62 = 123, you would ?
Ratling [72]
X-62=123
+62 +62
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you need to add a positive 62 from each side so -62+62=0 and 123+62=185
therefore, x=185
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Is a dodecahedron a 3 dimensional or a dodecagon a 3 dimensional ?
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Which piece of additional information can be used to prove that △rst ~ △vut? rt = st 3st = ut ∠r ≅ ∠v ∠v ≅ ∠u
Sunny_sXe [5.5K]

The option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

<h3>What is the similarity law for triangles?</h3>

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have given two triangles:

Triangle RST and Triangle VUT

AS we can see Line segment RS and UV are parallel.

Which is crossed by a transversal RV.

The angle SRV = Angle RVU

Thus, the option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

Learn more about the similarity of triangles here:

brainly.com/question/8045819

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3 0
2 years ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
4 years ago
Plzzzzzzzz help meeeeee
Westkost [7]

Answer:

1-120 in. 2-16cm 3-27 m

Step-by-step explanation:

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5 0
3 years ago
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