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Leviafan [203]
2 years ago
6

What are the solutions to X2 + 8X + 7 = 0?

Mathematics
2 answers:
8_murik_8 [283]2 years ago
5 0

Answer:

x = - 7, x = - 1

Step-by-step explanation:

Given

x² + 8x + 7 = 0

Consider the factors of the constant term (+ 7) which sum to give the coefficient of the x- term (+ 8)

The factors are + 7 and + 1 , since

7 × 1 = 7 and 7 + 1 = 8 , then

(x + 7)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x + 1 = 0 ⇒ x = - 1

Kipish [7]2 years ago
3 0

Answer:

x=-1,-7

Step-by-step explanation:

x^2+8x+7=0 where a \neq 0 so a = 1 b = 8 c = 7

Quadratic Formula: x=-b\frac{\sqrt{b^2-4ac} }{2a}

x=-8\frac{\sqrt{8^2-4(1)(7)} }{2(1)}

x=-8\frac{\sqrt{64-28} }{2}     Evaluate the exponent and multiply 4ac

x=-8\frac{\sqrt{36} }{2}          Subtract b^2 - 4ac and multiply 2a

x=-8\frac{\sqrt{6} }{2}           Solve for the sqrt root of 35

x = - 8 ± 6/2 =

x = - 8 + 6/2 = -1

x = - 8 - 6/2 = -7

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