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3 years ago

F(x)=x2+1 g(x)=5-1

1 answer:

7 0

Answer:Given that f ( x ) = 2 x − 3 f(x)=2x-3 f(x)=2x−3f, left parenthesis, x, right parenthesis, ... \end{aligned} (f⋅g)(x)=f(x)⋅g(x)=(2x−3)⋅(x+1)=2x2+2x−3x−3=2x2−x−3Define. ... Choose 1 answer: ... (Choice B) ... the new graph will pass through the two points (4, 0) and (6,-6) which only happens in Graph B. ... (c*d)(y) = (3y-4)(3-2y

Step-by-step explanation:

Just google it or do the math :)

p.s I googled it .

Hoped i helped you !

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The ratio of sam's age to Hank's age is 5 to 3.if the sum of their ages is 24, how old is Hank?

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Your class has 18 students. Exactly 2/3 of them say that, out of all their subjects, they like science the most. Which model sho

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Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less

STALIN [3.7K]

Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10 --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42 cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

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3 years ago

The endpoints of the diameter of a circle are (−2, −3) and (4, −1). Which equation represents the circle?

Alika [10]

Answer:

The equation of circle is $(x-1)^{2}$ + $(y-2)^{2}$ = 18

Step-by-step explanation:

Given the endpoints of the diameter of a circle: (-2,-3) and (4,-1)

We know that the equation of circle is

$(x-h)^{2}$ + $(y-k)^{2}$ = $r^{2}$

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

( $\frac{x1+x2}{2}$ , $\frac{y1+y2}{2}$ )

( $\frac{-2+4}{2}$ , $\frac{-3-1}{2}$ )

(1,2)

Hence (h,k) is (1,2)

Substituting values of (h.k) and (x.y) as (1,2) and (4,-1) respectively in equation of circle, we get

$(4-1)^{2}$ + $(-1-2)^{2}$ = $r^{2}$

$r^{2}$ = 18

Now substituting values of (h,k) and $r^{2}$ in equation of circle, we get

$(x-1)^{2}$ + $(y-2)^{2}$ = 18

Hence the equation of circle is $(x-1)^{2}$ + $(y-2)^{2}$ = 18

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