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jok3333 [9.3K]
3 years ago
9

Find the midpoint M of the line segment joining the points A = (-2, 8) and B = (-8, -4).

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

M (- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = A (- 2, 8 ) and (x₂, y₂ ) = B (- 8, - 4 ) , then

midpoint = ( \frac{-2-8}{2} , \frac{8-4}{2} ) = ( \frac{-10}{2} , \frac{4}{2} ) = (- 5, 2 )

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Eric has $25 to purchase magazines and to pay for his lunch. Each
faust18 [17]

Answer:

B

Step-by-step explanation:

The maximum amount Eric can spend on magazines is $25 less the cost of lunch, $15.

The appropriate inequality sign would be less than since he cannot spend more than $25.

Also, the amount he can spend on magazines would be what is left after paying for lunch.

So the correct inequality is 4m - 15 < 25

8 0
3 years ago
What is the math sentence for 3.46 and 0.346
Gnesinka [82]

Answer:

3.46 in a fraction

340.60

Step-by-step explanation:

The decimal 0.346 equals 34.6%

To convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 0.346 × 100 = 34.6% (answer).

➥ The ease way:

1) Move the decimal point two places to the right: 0.346 → 3.46 → 34.6.

2) Add a % sign: 34.6%

Answer: 34.6%

4 0
3 years ago
Read 2 more answers
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
4 years ago
-4d + 2(3 + d) = -14<br><br> Please help
soldi70 [24.7K]
-4d + 2(3+d)= -14
distribute the 2(3+d)
-4d + 6+ 2d= -14
Combine the like terms
-4d + 2d + 6= -14
-2d + 6 = -14
subtract 6 to -14 
-2d = -20
divide by -2
d= -20/-2
d= 10
Check your answer 
-4(10) + 2(3+ 10) = -14
-40 + 6 + 20
-40 + 26= -14
6 0
3 years ago
Read 2 more answers
How long will it take Birr 500
notka56 [123]

It would take 25 years for Birr 500 to quadruple if invested at a rate of 12% simple interest per annum.

<h3 /><h3>Simple interest formula</h3>

Using the simple interest formula A = P(1 + rt) where

  • P = princial amount = Birr 500,
  • A = final amount = 4P (since it is quadrupled),
  • r = rate = 12% = 12/100 = 0.12 and
  • t = time to quadruple
<h3 /><h3>Finding the time it takes to quadruple </h3>

Since we require t, making t subject of the formula, we have

t = [(A/P) - 1]/r

Substituting the values of the variables into the equation, we have

t = [(A/P) - 1]/r

t = [(4P/P) - 1]/0.12

t = [4 - 1]/0.12

t = 3/0.12

t = 25 years

So, it would take 25 years for Birr 500 to quadruple if invested at a rate of 12% simple interest per annum.

Learn more about simple interest here:

brainly.com/question/25793394

4 0
3 years ago
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