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Amanda [17]
3 years ago
13

A worker at a clothing store earns a 15 % commission on a sale of $75.00 . How much is the commission

Mathematics
1 answer:
aksik [14]3 years ago
7 0
15% = .15

75.00 x .15
 11.25
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Some help please! :) Branliest
sveta [45]

Answer:

Households without a vehicle were not surveyed. D

Step-by-step explanation:

I just finished with Maps testing like 10 minutes ago XD good luck!!

6 0
3 years ago
Which table does NOT represent a linear function?
chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 8, 5, 2, -1

- we subtract 3 each time

\rule{200}{2}

Let's try the next one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 5, 10, 15, 20

- we add 5 each time

\rule{200}{2}

Let's try the third one:

  • x values: -1, 0, 1, 2
  • - we add 1 each time
  • y values: 15, 18, 20, 21

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0
2 years ago
Write the equation for the line that passes through (3,4) and (2,-1) in slope intercept form
Lina20 [59]
Y=mx+b
m=4-1\3-2
3\1
y=3\1x+b
(u can take any of the 2 points.am taking the first one)
4=3\1(3)+b
4=9+b
4-9=b
-5=b
answer=
y=3\1x-5
5 0
3 years ago
7. Sylvia made a poster shaped like the triangle shown below. (1 point)
marta [7]
The answer would be 12 inches. I have the most faith in my answer.
7 0
3 years ago
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
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