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2 years ago

14

Find the tax amount given the original price and the tax rate. Round to the nearest cent if necessary. Original price: $58.73 Ta

x: 6.5%

1 answer:

Hoochie [10]2 years ago

7 0

$54.91

6.5% of 58.73.
Then minus that amount from 58.73

Mark brainliest please

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A United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year. A FLOC (Farm

disa [49]

Answer:

We conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

Step-by-step explanation:

We are given that a United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year.

A FLOC evaluation of 25 Mexican family units reveals a mean to be $30,000 with a sample standard deviation of $10,000.

Let $\mu$ = <em><u>true mean family income for Mexican migrants.</u></em>

So, Null Hypothesis, $H_0$ : $\mu$ = $27,000 {means that the mean family income for Mexican migrants to the United States is $27,000 per year}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $27,000 {means that the mean family income for Mexican migrants to the United States is different from $27,000 per year}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean family income = $30,000

s = sample standard deviation = $10,000

n = sample of Mexican family = 25

So, <u><em>the test statistics</em></u> = $\frac{30,000-27,000}{\frac{10,000}{\sqrt{25} } }$ ~ $t_2_4$

= 1.50

The value of t test statistics is 1.50.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -2.064 and 2.064 at 24 degree of freedom for two-tailed test.</u>

Since our test statistic lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

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3 years ago

Jackson spends 214 hours painting 212 pictures. He spends the same amount of time painting each picture. How much time, in hours

Wewaii [24]

1 hour and 7 1/2 minutes per picture
2 1/4 = 60 * 2 = 120 + 15 = 135/2= 67.5 = 1 hour and 7 1/2 minutes

3 0

3 years ago

Erwin earns $ 2 , 100 per month. Her deductions amount to 26 % of her paycheck. How much does Erwin take home each month?

Sergeu [11.5K]

Answer:

Credit ⇒ 45

Debit ⇒ $30

Step-by-step explanation:

Credit = $45

Debit = $30

When an account balance increases it means that it has been credited and when it decreases, it has been debited.

The beginning balance here is $0 and the closing balance is $15.

There were 2 transactions, one credit and one debit.

For the closing balance to be $15, the Credit amount must have been $15 more than the Debit amount.

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3 years ago

Find the measure of x

Jobisdone [24]

Answer:

Wdym

Step-by-step explanation:

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3 years ago

To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t

nikklg [1K]

Answer:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

$p_v =P(t_{(18)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=19.1$ represent the mean for the sample mean for 1

$\bar X_{2}=23.3$ represent the mean for the sample mean for 2

$s_{1}=4.818$ represent the sample standard deviation for the sample 1

$s_{2}=5.559$ represent the sample standard deviation for the sample 2

$n_{1}=10$ sample size selected 1

$n_{2}=10$ sample size selected 2

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \geq \mu_{2}$

Alternative hypothesis: $\mu_{1} < \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=10+10-2=18$

Since is a one sided test the p value would be:

$p_v =P(t_{(18)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

4 0

3 years ago