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Arisa [49]
4 years ago
13

On the weekend, I spent 6 3/5 hours reading and 1 1/4 hours at the gym. How much less time did I spend at the gym then reading?

Mathematics
1 answer:
Georgia [21]4 years ago
3 0
5 hours and 35 minutes
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Who knows how to do this ​
IgorC [24]

Answer:

<h2>144 {cm}^{2}</h2>

Step-by-step explanation:

Given,

As we know that the all sides of the square are equal.

Length of a square paper = 12 cm

Area of square = ?

Now, let's find the area of square

=  {l}^{2}

plugging the value of length,

{(12)}^{2}

Evaluate the power

= 144 square cm

Hope this helps...

Best regards!!

7 0
3 years ago
How many times greater is 130,000,000 than 64,800,000?
insens350 [35]
\frac{130,000,000}{64,800,000} = \frac{1,300}{648} =\boxed {2.00617283951}
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4 years ago
What would you do to isolate the variable in the equation below, using only one
weeeeeb [17]
Subtract 9 from both sides of the equation
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How can you write 182 as a sum of Hundreds,tens,and ones
navik [9.2K]
1 hundred, 8 tens, and 2 ones
8 0
4 years ago
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10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
4 years ago
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