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Elina [12.6K]
2 years ago
12

Which ordered pair is a solution of the equation y=x-3?

Mathematics
1 answer:
labwork [276]2 years ago
4 0

Answer:

D is your answer

Step-by-step explanation:

y = x - 3

y = 2

x = 5

now insert the x and y into the equation

2 = 5 - 3

then subtract

2 = 2

last to find out if your right when both numbers equal each other like 2 = 2 then that will be you answer to your problem

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I do not know the answer​
Vaselesa [24]

Answer:

5 1 over 4

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ME WITH THIS ASAP X
joja [24]

Answer:

Hi i think it is 6 im not sure though

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What was the final price of the wind chime?
svet-max [94.6K]

Answer:

$29.93

Step-by-step explanation:

First, we take the discount off of the original price.

We need to find the discount amount in dollars.

30/100=.3 this is 1%.

.3 * 5 = 1.5 He will get $1.50 off of his purchase.

30 - 1.5 = 28.5.

Next we will add tax. We need to find tax in dollars.

28.5/100=.285 this is 1%

.285 * 5 = 1.43 He will get $1.43 of tax on his purchase.

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6 0
3 years ago
Can someone help me with this and also explain please
sveticcg [70]
13n+4
there is an equal difference between each number where four is added on each time, so you would add for on to the last number which would give you the 13 and use the +4 at the end to show the differences between the numbers
3 0
3 years ago
Write a quadratic equation in standard form with x-intercepts (-3, 0) and (4, 0) that passes through (2, -20).
jeka57 [31]

Answer:

The equation in standard form is: y=2x^2-2x-24

Step-by-step explanation:

Since they give you the x-intercepts (the zeros of the quadratic expression) one knows that the binomials: (x-(-3)) and (x-4) must be factors of the quadratic expression.

We can therefore write the equation as:

y=k\,(x+3)(x-4)

using the binomial factors given above, and a numerical factor "k" that we can determine by using the information that the graph passes through the point (2,-20):

y=k\,(x+3)(x-4)\\-20=k\,(2+3)(2-4)\\-20=k\,(5)(-2)\\-20=k\,(-10)\\k=\frac{-20}{-10} \\k=2

Then,the equation can be written as:

y=2\,(x+3)(x-4)\\y=2(x^2-x-12)\\y=2x^2-2x-24

where we wrote the equation already in standard form

5 0
2 years ago
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