Question

A local company manufactures netbook computers. Their profit function is given by this equation: y equal minus x to the power of 2 plus 120 x plus 3000 where x is the number of netbooks produced in one day and y is the profit (in dollars) the company makes that day. What is the maximum profit that the company can make? (Hint: Find the vertex of the parabola.)

Answer 1

Answer: $6,600

Step-by-step explanation:

Given: The profit function is given by the equation:

$y=-x^2+120x+3000$,where x is the number of netbooks produced in one day and y is the profit (in dollars) the company makes that day.

To find the maximum profit, first we need to find critical point of the function.

For that, first differentiate the above function w.r.t. x, we get

$y'=-2x+120$

Now, Put $y'=0$, we get

$-2x+120=0\\\\\Rightarrow\ x=60$

Again differentiate the above function w.r.t. x, we get

$y"=-2$

By second derivative test, at x=60 , attains its maximum value.

Now, the Maximum profit will be :

$y=-(60)^2+120(60)+3,000=6,600$

Hence, the maximum profit that the company can make = $6,600

Answer 2

Answer by BlueSky06

The equation described above can also be written as,                    y = -x² + 100x + 4000To get the number of notebooks that will give them the maximum profit, we derive the equation and equate to zero.                  dy/dx = -2x + 100 = 0The value of x from the equation is 50. Then, we substitute 50 to the original equation to get the profit.                    y = -(50^2) + 100(50) + 4000 = 6500Thus, the maximum profit that the company makes is $6,500/day. 
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