I am soo confused can ya'll help me plz? Thx.

The nth term of a sequence is given by 2n²+1.Write down the first four terms of the sequence.

ivanzaharov [21]

Answer:

2(1)²−1= 1

2(2)²−1= 7

2(3)²−1= 17

2(4)²−1= 31

2(5)²−1= 49

Please mark as brainliest if answer is right

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5 0

2 years ago

HELPPPP 100 points if you help!!!!

nignag [31]

Answer:

Part A)

Chorus:

$c(t)=15(1.12)^t$

Band:

$b(t)=2t+30$

Part B)

After 9 years:

The chorus will have about 41 people.

And the band will have 48 people.

Part C)

About approximately 11 years.

Step-by-step explanation:

We are given that there are 15 people in the chorus. Each year, number of people in the chorus increases by 12%. So, the chorus increases exponentially.

There are 30 people in the band. Each year, 2 new people join the band. So, the band increases linearly.

Part A)

Since after each year, the number of people in the chorus increases by 12%, the new population will be 112% or 1.12 of the previous population.

So, using the standard form for exponential growth:

$c(t)=a(r)^t$

Where a is the initial population and r is the rate of change.

We will substitute 15 for a and 1.12 for r. Hence:

$c(t)=15(1.12)^t$

This represents the number of people in the chorus after t years.

We are given that 2 new people join the band each year. So, it increases linearly.

Since there are already 30 people in the band, our initial point or y-intercept is 30.

And since 2 new people join every year, our slope is 2. Then by the slope-intercept form:

$b(t)=mt+b$

And by substitution:

$b(t)=2t+30$

This represents the number of people in the band after t years.

Part B)

We want to find the number of people in the chorus and the band after 9 years.

Using the chorus function, we see that:

$c(9)=15(1.12)^9\approx41.59\approx41$

There will be approximately 41 people in the chorus after 9 years.

And using the band function, we see that:

$b(9)=2(9)+30=48$

There will be 48 people in the band after 9 years.

Part C)

We want to determine after approximately how many years will the number of people in the chorus and band be equivalent. Hence, we will set the two functions equal to each other and solve for t. So:

$15(1.12)^t=2t+30$

Unfortunately, it is impossible to solve for t using normal analytic methods. Hence, we can graph them. Recall that graphically, our equation is the same as saying at what point will our two functions intersect.

Referring to the graph below, we can see that the point of intersection is at approximately (10.95, 51.91).

Hence, after approximately 11 years, both the chorus and the band will have approximately 52 people.

5 0

3 years ago

Solve for k: 1/3k + 1/2 = 1/4k

son4ous [18]

$\frac{1}{3}k+\frac{1}{2}=\frac{1}{4}k\ \ \ \ \ \ |\cdot12(to\ eliminate\ fractions)\\\\\frac{12}{3}k+\frac{12}{2}=\frac{12}{4}k\\\\4k+6=3k\\\\4k-3k=-6\\\\k=-6$

3 0

3 years ago

Please help! Two math problems!!!

Fynjy0 [20]

Answer:

Tell me if i am wrong. :)

Step-by-step explanation:

To solve for y:

Q.1 2x + y = -1

y = -1 - 2x

Q. 2. 4x - 5y = 7

y = 7 - 4x over -5

3 0

3 years ago

What translation rule can be used to describe the result of the composition of T < 4, −10 >(x, y) and T < −1, −9 >(x

Vikki [24]

The first translation picks a point and adds 4 to its x coordinate, and subtracts 10 from the y coordinate. In other words, it moves the point 4 units to the right and 10 units down.

Similarly, the second translation subtracts 1 to the x coordinate, and subtracts 9 from the y coordinate. In other words, it moves the point 1 unit to the left and 9 units down.

So, if you perform one translation after the other, you move the point 4 units to the right and 1 unit to the left along the x axis, and 10 units down and 9 more units down along the y axis.

The net result is a translation of 3 units to the right and 19 units down.

6 0

3 years ago