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padilas [110]
3 years ago
12

Can u hurry and help please

Mathematics
2 answers:
myrzilka [38]3 years ago
6 0

Answer:

18.84

The equation for circumference is 2πr which means that you times 2 by pi and then the radius which is 6 divided by 2 so 3. Then you get 6π which is 18.84

Oksi-84 [34.3K]3 years ago
4 0

Answer:

18.84

Step-by-step explanation:

Hope this helps :)

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The equations are given below.
amid [387]

Answer:

neither

Step-by-step explanation:

they are parallel when they have the same slope and perpendicular when the slope is completely different

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3 years ago
Based on the pattern in the table what is the value of A
Arlecino [84]
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The denominator has a pattern , if you look through it carefully each denominator is multiply by 2. There for you multiply 32 x 2 which gives you 64 so it’s 1/64. If you wanna confirm it , you could use a calculator to check your answer.


5 0
4 years ago
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Find a solution to the linear equation 13x+y=26
Anna11 [10]

Answer:

y = -13x+26

Step-by-step explanation:

13x+y=26

y= -13x+26

8 0
3 years ago
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Darya [45]

Answer:

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3 0
4 years ago
Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.
GREYUIT [131]

Answer:

y=\dfrac{1}{1-Ke^{-t}}

Step-by-step explanation:

Given

The given equation is a differential equation

\dfrac{dy}{dt}=y-y^2

\dfrac{dy}{dt}=-(y^2-y)

By separating variable

⇒\dfrac{dy}{(y^2-y)}=-t

\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt

Now by taking integration both side

\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt

⇒\ln (y-1)-\ln y=-t+C

Where C is the constant

\ln \dfrac{y-1}{y}=-t+C

\dfrac{y-1}{y}=e^{-t+c}

\dfrac{y-1}{y}=Ke^{-t}

y=\dfrac{1}{1-Ke^{-t}}

from above equation we can say that

When t  will increases in positive direction then e^{-t} will decreases it means that {1-Ke^{-t}} will increases, so y will decreases. Similarly in the case of negative t.

4 0
3 years ago
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