Step-by-step explanation:
2πrh+2πr²=surface area
2π(3)(6)+2π(3²)
36π+18π
54π
<u>Answer-</u>
<em>The polynomial function is,</em>

<u>Solution-</u>
The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1
The general form of the equation will be,
( ∵ (3-i) is the conjugate of (3+i) )








Therefore, this is the required polynomial function.
Hello,
As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}
Answer C